Problem with solution: Create a Plate Capacitor with a Certain Capacitance

A charged plate capacitor with dielectric
Plate codensator with area \( A \), charge \( Q \), distance \( d \), voltage \( U \) and the dielectric between the plates.

Capacitors are characterized by the electrical capacitance. It tells you how good a capacitor can "store" electric charge. The goal of modern technology is usually to produce the smallest possible capacitors with the largest possible capacitance so that such a component also fits into your smartphone.

You want to have a plate capacitor which has a capacitance of \( C = 0.5 \, \text{nF} \) (nano farad). The area of a capacitor plate is given as \( A = 12 \, \text{cm}^2 \).

  1. How large do you have to choose the distance \( d \) of the plates to reach this capacitance?

  2. What else can you do to achieve the specified capacitance when the plate distance is set to \( d = 1.5 \, \text{mm} \)?

Solution tips

All you need is the formula for the capacitance of a plate capacitor.

Solution for (a)
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Plattenabstand mittels Kapazität
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Plattenabstand konkret berechnet
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Solution for (b)
Relative Permittivität mittels Kapazität
Formula anchor
Relative Permittivität konkret berechnet
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