Formula: Charge in an Electric Field Force Electric charge
Electric force
$$ \boldsymbol{F} $$ Unit $$ \mathrm{N} = \frac{\mathrm{kg} \, \mathrm{m}}{\mathrm{s}^2} $$If you place a charge \( q \) in an electric field \( E \), this charge is accelerated along the field lines by the electric force. A positive charge is accelerated in the direction of the electric field lines and a negative charge is accelerated against the electric field lines.
Electric charge
$$ q $$ Unit $$ \mathrm{C} = \mathrm{As} $$The charge determines in which direction the electric force points - you can see this by its sign. For positive charges, the sign is a plus - so a force acts on this particle in the direction of the electric field lines. This is the case, for example, with protons, alpha particles, or positively charged ions, such as \( \text{Na}^+ \). For negative charges, the sign is a minus - so a force acts on this particle against the electric field lines. You can observe this for example with electrons.
An electron carries a negative charge \( q ~=~ -1.602 \cdot 10^{-19} \, \text{C} \). A proton, on the other hand, carries a positive charge: \( q ~=~ +1.602 \cdot 10^{-19} \, \text{C} \). Negative charges have a minus before the value of the charge and positive charges have a plus.
Electric field
$$ \class{purple}{\boldsymbol E} $$ Unit $$ \frac{\mathrm{V}}{\mathrm{m}} = \frac{\mathrm{N}}{\mathrm{C}} = \frac{\mathrm{kg} \, \mathrm{m}}{\mathrm{A} \, \mathrm{s}^3} $$Sconvert the formula according to the electric field strength: \( E ~=~ \frac{F_{ \text{E} }}{q} \), as you can see it is "force per charge".
During a thunderstorm, for example, there is a very large electric field between the earth and clouds; it reaches values above \( 150 \, 000 \, \frac{\text V}{\text m} \).
The electric field generated by a charged particle (e.g. an electron) can be determined by Coulomb's law.