This is the time interval between two events that passes on the moving clock from the point of view of an observer at rest. Since the gamma factor \(\gamma\) is greater than 1:

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$$ \gamma ~=~ \frac{1}{ \sqrt{1 ~-~ \frac{v^2}{c^2}} } > 1 $$
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\(\Delta t'\) is greater than \(\Delta t\). Consequently, a stationary observer sees that more time \(\Delta t'\) has elapsed on the moving clock than on his stationary clock, \(\Delta t\).

If the moving clock moves with velocity \( v = 2 \cdot 10^8 \, \frac{\text m}{\text s} \) relative to the stationary observer, the gamma factor is:
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\[ \gamma ~=~ \frac{1}{ \sqrt{1 ~-~ \frac{(2 \cdot 10^8 \, \frac{\text m}{\text s})^2}{(2 \cdot 10^8 \, \frac{\text m}{\text s})^2}} } ~=~ 1.7 \]
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Now, if time \(\Delta t = 1 \, \text{s}\) has passed on the clock of an observer at rest, more time has passed on the clock in motion:
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\[ \Delta t' ~=~ \gamma \, \Delta t ~=~ 1.7 \,\text{s} \]
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