Formula: 1. Maxwell Equation in Integral Form Electric field (E field) Electric charge
$$\oint_A \class{blue}{\boldsymbol{E}} ~\cdot~ \text{d}\boldsymbol{a} ~=~ \frac{\class{red}{Q}}{\varepsilon_0}$$
Electric field
$$ \class{blue}{\boldsymbol{E}} $$ Unit $$ \frac{\mathrm{V}}{\mathrm{m}} = \frac{\mathrm{N}}{\mathrm{C}} = \frac{\mathrm{kg} \, \mathrm{m}}{\mathrm{A} \, \mathrm{s}^3} $$
This quantity is a vector field (it assigns a field vector to each point in space) and tells how large the electric force on a test charge would be if it were placed in a particular location.
Surface
$$ A $$
The (imaginary) surface over which the electric field \( \class{blue}{\boldsymbol{E}} \) is integrated. This can be, for example, a spherical surface or a cylindrical surface. For example, to calculate the \( \class{blue}{\boldsymbol{E}} \) field inside a charged sphere, this imaginary surface is placed inside the charged sphere.
Here \( \text{d}\boldsymbol{a} \) is a infinitesimal piece of the surface. By definition the direction of \(\text{d}\boldsymbol{a}\) is perpendicular on the surface.
Electric charge
$$ \class{red}{Q} $$ Unit $$ \mathrm{C} = \mathrm{As} $$
This is the charge that is enclosed by the selected surface \( A \).
Vacuum Permittivity
$$ \varepsilon_0 $$ Unit $$ \frac{\mathrm{As}}{\mathrm{Vm}} $$
The vacuum permittivity is a physical constant that appears in equations involving electromagnetic fields. It has the following experimentally determined value:
$$ \varepsilon_0 ~\approx~ 8.854 \, 187 \, 8128 ~\cdot~ 10^{-12} \, \frac{\mathrm{As}}{\mathrm{Vm}} $$